R(x)=x(200-4x)C(x)=160+20x

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Solution for R(x)=x(200-4x)C(x)=160+20x equation: 



(R)=R(200-4R)(R)=160+20R

We move all terms to the left:

(R)-(R(200-4R)(R))=0

We add all the numbers together, and all the variables

R-(R(-4R+200)R)=0



We calculate terms in parentheses: -(R(-4R+200)R), so:

R(-4R+200)R

We multiply parentheses

-4R^3+200R^2

We do not support eRpression: R^3

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