2y*3y=40

Solution for 2y*3y=40 equation:

2y*3y=40

We move all terms to the left:

2y*3y-(40)=0

Wy multiply elements

6y^2-40=0

a = 6; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·6·(-40)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*6}=\frac{0-8\sqrt{15}}{12}
=-\frac{8\sqrt{15}}{12}
=-\frac{2\sqrt{15}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*6}=\frac{0+8\sqrt{15}}{12}
=\frac{8\sqrt{15}}{12}
=\frac{2\sqrt{15}}{3}
$