(X-5)(x+2)=(x-7)(x-3)+4

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Solution for (X-5)(x+2)=(x-7)(x-3)+4 equation: 



(X-5)(X+2)=(X-7)(X-3)+4

We move all terms to the left:

(X-5)(X+2)-((X-7)(X-3)+4)=0

We multiply parentheses ..

(+X^2+2X-5X-10)-((X-7)(X-3)+4)=0



We calculate terms in parentheses: -((X-7)(X-3)+4), so:

(X-7)(X-3)+4

We multiply parentheses ..

(+X^2-3X-7X+21)+4

We get rid of parentheses

X^2-3X-7X+21+4

We add all the numbers together, and all the variables

X^2-10X+25

Back to the equation:

-(X^2-10X+25)



We get rid of parentheses

X^2-X^2+2X-5X+10X-10-25=0

We add all the numbers together, and all the variables

7X-35=0

We move all terms containing X to the left, all other terms to the right

7X=35

X=35/7

X=5

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