(3x-5)+(7x-2)+(x)=180

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Solution for (3x-5)+(7x-2)+(x)=180 equation: 



(3x-5)+(7x-2)+(x)=180

We move all terms to the left:

(3x-5)+(7x-2)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(3x-5)+(7x-2)-180=0

We get rid of parentheses

x+3x+7x-5-2-180=0

We add all the numbers together, and all the variables

11x-187=0

We move all terms containing x to the left, all other terms to the right

11x=187

x=187/11

x=17

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