(W)+(w)+(2w+3)+(2w+3)=48

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Solution for (W)+(w)+(2w+3)+(2w+3)=48 equation: 



()+(W)+(2W+3)+(2W+3)=48

We move all terms to the left:

()+(W)+(2W+3)+(2W+3)-(48)=0

determiningTheFunctionDomain
W+(2W+3)+(2W+3)-48+()=0

We add all the numbers together, and all the variables

W+(2W+3)+(2W+3)=0

We get rid of parentheses

W+2W+2W+3+3=0

We add all the numbers together, and all the variables

5W+6=0

We move all terms containing W to the left, all other terms to the right

5W=-6

W=-6/5

W=-1+1/5

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