4(b-6)=3(b+2)

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Solution for 4(b-6)=3(b+2) equation: 



4(b-6)=3(b+2)

We move all terms to the left:

4(b-6)-(3(b+2))=0

We multiply parentheses

4b-(3(b+2))-24=0



We calculate terms in parentheses: -(3(b+2)), so:

3(b+2)

We multiply parentheses

3b+6

Back to the equation:

-(3b+6)



We get rid of parentheses

4b-3b-6-24=0

We add all the numbers together, and all the variables

b-30=0

We move all terms containing b to the left, all other terms to the right

b=30

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