3(u+2)-u=2(u-1)

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Solution for 3(u+2)-u=2(u-1) equation: 



3(u+2)-u=2(u-1)

We move all terms to the left:

3(u+2)-u-(2(u-1))=0

We add all the numbers together, and all the variables

-1u+3(u+2)-(2(u-1))=0

We multiply parentheses

-1u+3u-(2(u-1))+6=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

2u-(2u-2)+6=0

We get rid of parentheses

2u-2u+2+6=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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