(9x/(3x-1))+(4/(3x+1))=3

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Solution for (9x/(3x-1))+(4/(3x+1))=3 equation: 



(9x/(3x-1))+(4/(3x+1))=3

We move all terms to the left:

(9x/(3x-1))+(4/(3x+1))-(3)=0



Domain of the equation: (3x-1))!=0

x∈R





Domain of the equation: (3x+1))!=0

x∈R



We calculate fractions


(27x^2+9x)/((3x-1))*3x+(12x-4)/((3x-1))*3x-3=0

We multiply all the terms by the denominator


(27x^2+9x)+(12x-4)-3*((3x-1))*3x=0

We get rid of parentheses

27x^2+9x+12x-3*((3x-1))*3x-4=0

We add all the numbers together, and all the variables

27x^2+21x-3*((3x-1))*3x-4=0

We move all terms containing x to the left, all other terms to the right

27x^2+21x-3*((3x-1))*3x=4

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