2/3(x-5)=1/4(x+20)

Solution for 2/3(x-5)=1/4(x+20) equation:

2/3(x-5)=1/4(x+20)

We move all terms to the left:

2/3(x-5)-(1/4(x+20))=0


Domain of the equation: 3(x-5)!=0

x∈R



Domain of the equation: 4(x+20))!=0

x∈R


We calculate fractions


(8xx/(3(x-5)*4(x+20)))+(-3xx/(3(x-5)*4(x+20)))=0


We calculate terms in parentheses: +(8xx/(3(x-5)*4(x+20))), so:

8xx/(3(x-5)*4(x+20))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)



We calculate terms in parentheses: +(-3xx/(3(x-5)*4(x+20))), so:

-3xx/(3(x-5)*4(x+20))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

8xx-3xx=0