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2(y+1)-3y=5(y-1)
We move all terms to the left:
2(y+1)-3y-(5(y-1))=0
We add all the numbers together, and all the variables
-3y+2(y+1)-(5(y-1))=0
We multiply parentheses
-3y+2y-(5(y-1))+2=0
We calculate terms in parentheses: -(5(y-1)), so:We add all the numbers together, and all the variables
5(y-1)
We multiply parentheses
5y-5
Back to the equation:
-(5y-5)
-1y-(5y-5)+2=0
We get rid of parentheses
-1y-5y+5+2=0
We add all the numbers together, and all the variables
-6y+7=0
We move all terms containing y to the left, all other terms to the right
-6y=-7
y=-7/-6
y=1+1/6
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