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(9x+8)(7x-10)=0
We multiply parentheses ..
(+63x^2-90x+56x-80)=0
We get rid of parentheses
63x^2-90x+56x-80=0
We add all the numbers together, and all the variables
63x^2-34x-80=0
a = 63; b = -34; c = -80;
Δ = b2-4ac
Δ = -342-4·63·(-80)
Δ = 21316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{21316}=146$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-146}{2*63}=\frac{-112}{126} =-8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+146}{2*63}=\frac{180}{126} =1+3/7 $
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