-4(4y-4)-y=-3(y-2)

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Solution for -4(4y-4)-y=-3(y-2) equation: 



-4(4y-4)-y=-3(y-2)

We move all terms to the left:

-4(4y-4)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-4(4y-4)-(-3(y-2))=0

We multiply parentheses

-1y-16y-(-3(y-2))+16=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-17y-(-3y+6)+16=0

We get rid of parentheses

-17y+3y-6+16=0

We add all the numbers together, and all the variables

-14y+10=0

We move all terms containing y to the left, all other terms to the right

-14y=-10

y=-10/-14

y=5/7

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