12/13t+3/26=81/78t=

Solution for 12/13t+3/26=81/78t= equation:

12/13t+3/26=81/78t=

We move all terms to the left:

12/13t+3/26-(81/78t)=0


Domain of the equation: 13t!=0

t!=0/13

t!=0

t∈R



Domain of the equation: 78t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

12/13t-(+81/78t)+3/26=0

We get rid of parentheses

12/13t-81/78t+3/26=0

We calculate fractions


21294t^2/52728t^2+48672t/52728t^2+(-54756t)/52728t^2=0

We multiply all the terms by the denominator


21294t^2+48672t+(-54756t)=0

We get rid of parentheses

21294t^2+48672t-54756t=0

We add all the numbers together, and all the variables

21294t^2-6084t=0

a = 21294; b = -6084; c = 0;
Δ = b2-4ac
Δ = -60842-4·21294·0
Δ = 37015056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{37015056}=6084$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6084)-6084}{2*21294}=\frac{0}{42588}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6084)+6084}{2*21294}=\frac{12168}{42588}
=2/7
$