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(9x+51)=(3x+45)
We move all terms to the left:
(9x+51)-((3x+45))=0
We get rid of parentheses
9x-((3x+45))+51=0
We calculate terms in parentheses: -((3x+45)), so:We get rid of parentheses
(3x+45)
We get rid of parentheses
3x+45
Back to the equation:
-(3x+45)
9x-3x-45+51=0
We add all the numbers together, and all the variables
6x+6=0
We move all terms containing x to the left, all other terms to the right
6x=-6
x=-6/6
x=-1
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