(3x+45)=(9x+51)

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Solution for (3x+45)=(9x+51) equation: 



(3x+45)=(9x+51)

We move all terms to the left:

(3x+45)-((9x+51))=0

We get rid of parentheses

3x-((9x+51))+45=0



We calculate terms in parentheses: -((9x+51)), so:

(9x+51)

We get rid of parentheses

9x+51

Back to the equation:

-(9x+51)



We get rid of parentheses

3x-9x-51+45=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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