(8-w)(2w+3)=0

Solution for (8-w)(2w+3)=0 equation:

(8-w)(2w+3)=0

We add all the numbers together, and all the variables

(-1w+8)(2w+3)=0

We multiply parentheses ..

(-2w^2-3w+16w+24)=0

We get rid of parentheses

-2w^2-3w+16w+24=0

We add all the numbers together, and all the variables

-2w^2+13w+24=0

a = -2; b = 13; c = +24;
Δ = b2-4ac
Δ = 132-4·(-2)·24
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*-2}=\frac{-32}{-4}
=+8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*-2}=\frac{6}{-4}
=-1+1/2
$