(9x+41)=(5x-1)

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Solution for (9x+41)=(5x-1) equation: 



(9x+41)=(5x-1)

We move all terms to the left:

(9x+41)-((5x-1))=0

We get rid of parentheses

9x-((5x-1))+41=0



We calculate terms in parentheses: -((5x-1)), so:

(5x-1)

We get rid of parentheses

5x-1

Back to the equation:

-(5x-1)



We get rid of parentheses

9x-5x+1+41=0

We add all the numbers together, and all the variables

4x+42=0

We move all terms containing x to the left, all other terms to the right

4x=-42

x=-42/4

x=-10+1/2

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