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(2x-5)(5x-4)=180
We move all terms to the left:
(2x-5)(5x-4)-(180)=0
We multiply parentheses ..
(+10x^2-8x-25x+20)-180=0
We get rid of parentheses
10x^2-8x-25x+20-180=0
We add all the numbers together, and all the variables
10x^2-33x-160=0
a = 10; b = -33; c = -160;
Δ = b2-4ac
Δ = -332-4·10·(-160)
Δ = 7489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{7489}}{2*10}=\frac{33-\sqrt{7489}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{7489}}{2*10}=\frac{33+\sqrt{7489}}{20} $
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