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(9x+1)=(3x+8)
We move all terms to the left:
(9x+1)-((3x+8))=0
We get rid of parentheses
9x-((3x+8))+1=0
We calculate terms in parentheses: -((3x+8)), so:We get rid of parentheses
(3x+8)
We get rid of parentheses
3x+8
Back to the equation:
-(3x+8)
9x-3x-8+1=0
We add all the numbers together, and all the variables
6x-7=0
We move all terms containing x to the left, all other terms to the right
6x=7
x=7/6
x=1+1/6
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