7(2q-3)=21q+21

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Solution for 7(2q-3)=21q+21 equation: 



7(2q-3)=21q+21

We move all terms to the left:

7(2q-3)-(21q+21)=0

We multiply parentheses

14q-(21q+21)-21=0

We get rid of parentheses

14q-21q-21-21=0

We add all the numbers together, and all the variables

-7q-42=0

We move all terms containing q to the left, all other terms to the right

-7q=42

q=42/-7

q=-6

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