5m(m-1)+16(2m+3)=3(2m-7)-m

Solution for 5m(m-1)+16(2m+3)=3(2m-7)-m equation:

5m(m-1)+16(2m+3)=3(2m-7)-m

We move all terms to the left:

5m(m-1)+16(2m+3)-(3(2m-7)-m)=0

We multiply parentheses

5m^2-5m+32m-(3(2m-7)-m)+48=0


We calculate terms in parentheses: -(3(2m-7)-m), so:

3(2m-7)-m

We add all the numbers together, and all the variables

-1m+3(2m-7)

We multiply parentheses

-1m+6m-21

We add all the numbers together, and all the variables

5m-21

Back to the equation:

-(5m-21)


We add all the numbers together, and all the variables

5m^2+27m-(5m-21)+48=0

We get rid of parentheses

5m^2+27m-5m+21+48=0

We add all the numbers together, and all the variables

5m^2+22m+69=0

a = 5; b = 22; c = +69;
Δ = b2-4ac
Δ = 222-4·5·69
Δ = -896
Delta is less than zero, so there is no solution for the equation