(9c+9)-(7c-8)=27-3c

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Solution for (9c+9)-(7c-8)=27-3c equation: 



(9c+9)-(7c-8)=27-3c

We move all terms to the left:

(9c+9)-(7c-8)-(27-3c)=0

We add all the numbers together, and all the variables

(9c+9)-(7c-8)-(-3c+27)=0

We get rid of parentheses

9c-7c+3c+9+8-27=0

We add all the numbers together, and all the variables

5c-10=0

We move all terms containing c to the left, all other terms to the right

5c=10

c=10/5

c=2

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