(4x-30)=(3x+5)

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Solution for (4x-30)=(3x+5) equation: 



(4x-30)=(3x+5)

We move all terms to the left:

(4x-30)-((3x+5))=0

We get rid of parentheses

4x-((3x+5))-30=0



We calculate terms in parentheses: -((3x+5)), so:

(3x+5)

We get rid of parentheses

3x+5

Back to the equation:

-(3x+5)



We get rid of parentheses

4x-3x-5-30=0

We add all the numbers together, and all the variables

x-35=0

We move all terms containing x to the left, all other terms to the right

x=35

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