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x(x-3)+4=x(2-x)
We move all terms to the left:
x(x-3)+4-(x(2-x))=0
We add all the numbers together, and all the variables
x(x-3)-(x(-1x+2))+4=0
We multiply parentheses
x^2-3x-(x(-1x+2))+4=0
We calculate terms in parentheses: -(x(-1x+2)), so:We get rid of parentheses
x(-1x+2)
We multiply parentheses
-1x^2+2x
Back to the equation:
-(-1x^2+2x)
x^2+1x^2-2x-3x+4=0
We add all the numbers together, and all the variables
2x^2-5x+4=0
a = 2; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·2·4
Δ = -7
Delta is less than zero, so there is no solution for the equation
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