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(8x+5)(7x+8)=0
We multiply parentheses ..
(+56x^2+64x+35x+40)=0
We get rid of parentheses
56x^2+64x+35x+40=0
We add all the numbers together, and all the variables
56x^2+99x+40=0
a = 56; b = 99; c = +40;
Δ = b2-4ac
Δ = 992-4·56·40
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-29}{2*56}=\frac{-128}{112} =-1+1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+29}{2*56}=\frac{-70}{112} =-5/8 $
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