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3/n=n+1
We move all terms to the left:
3/n-(n+1)=0
Domain of the equation: n!=0We get rid of parentheses
n∈R
3/n-n-1=0
We multiply all the terms by the denominator
-n*n-1*n+3=0
We add all the numbers together, and all the variables
-1n-n*n+3=0
Wy multiply elements
-1n^2-1n+3=0
a = -1; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·(-1)·3
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{13}}{2*-1}=\frac{1-\sqrt{13}}{-2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{13}}{2*-1}=\frac{1+\sqrt{13}}{-2} $
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