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(x-3)-2(x-3)=2x+3
We move all terms to the left:
(x-3)-2(x-3)-(2x+3)=0
We multiply parentheses
(x-3)-2x-(2x+3)+6=0
We get rid of parentheses
x-2x-2x-3-3+6=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0
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