(8x+2)+(4x+6)=(20x-40)

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Solution for (8x+2)+(4x+6)=(20x-40) equation: 



(8x+2)+(4x+6)=(20x-40)

We move all terms to the left:

(8x+2)+(4x+6)-((20x-40))=0

We get rid of parentheses

8x+4x-((20x-40))+2+6=0



We calculate terms in parentheses: -((20x-40)), so:

(20x-40)

We get rid of parentheses

20x-40

Back to the equation:

-(20x-40)



We add all the numbers together, and all the variables

12x-(20x-40)+8=0

We get rid of parentheses

12x-20x+40+8=0

We add all the numbers together, and all the variables

-8x+48=0

We move all terms containing x to the left, all other terms to the right

-8x=-48

x=-48/-8

x=+6

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