(6x+5)=(4x+45)+(3x)

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Solution for (6x+5)=(4x+45)+(3x) equation: 



(6x+5)=(4x+45)+(3x)

We move all terms to the left:

(6x+5)-((4x+45)+(3x))=0

We get rid of parentheses

6x-((4x+45)+3x)+5=0



We calculate terms in parentheses: -((4x+45)+3x), so:

(4x+45)+3x

We add all the numbers together, and all the variables

3x+(4x+45)

We get rid of parentheses

3x+4x+45

We add all the numbers together, and all the variables

7x+45

Back to the equation:

-(7x+45)



We get rid of parentheses

6x-7x-45+5=0

We add all the numbers together, and all the variables

-1x-40=0

We move all terms containing x to the left, all other terms to the right

-x=40

x=40/-1

x=-40

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