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4p+2=4/3p+3
We move all terms to the left:
4p+2-(4/3p+3)=0
Domain of the equation: 3p+3)!=0We get rid of parentheses
p∈R
4p-4/3p-3+2=0
We multiply all the terms by the denominator
4p*3p-3*3p+2*3p-4=0
Wy multiply elements
12p^2-9p+6p-4=0
We add all the numbers together, and all the variables
12p^2-3p-4=0
a = 12; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·12·(-4)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{201}}{2*12}=\frac{3-\sqrt{201}}{24} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{201}}{2*12}=\frac{3+\sqrt{201}}{24} $
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