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(8m-5)(8m+5)=0
We use the square of the difference formula
64m^2-25=0
a = 64; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·64·(-25)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*64}=\frac{-80}{128} =-5/8 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*64}=\frac{80}{128} =5/8 $
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