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1x/3x+4=3x/2x+3
We move all terms to the left:
1x/3x+4-(3x/2x+3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
1x/3x-3x/2x-3+4=0
We calculate fractions
(-9x^2)/6x^2+2x^2/6x^2-3+4=0
We add all the numbers together, and all the variables
(-9x^2)/6x^2+2x^2/6x^2+1=0
We multiply all the terms by the denominator
(-9x^2)+2x^2+1*6x^2=0
We add all the numbers together, and all the variables
2x^2+(-9x^2)+1*6x^2=0
Wy multiply elements
2x^2+(-9x^2)+6x^2=0
We get rid of parentheses
2x^2-9x^2+6x^2=0
We add all the numbers together, and all the variables
-1x^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-2}=0$
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