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2(2x+3)-7x=18+5(x2x)
We move all terms to the left:
2(2x+3)-7x-(18+5(x2x))=0
We add all the numbers together, and all the variables
2(2x+3)-7x-(5x2x+18)=0
We add all the numbers together, and all the variables
-7x+2(2x+3)-(5x2x+18)=0
We multiply parentheses
-7x+4x-(5x2x+18)+6=0
We get rid of parentheses
-7x+4x-5x2x-18+6=0
We add all the numbers together, and all the variables
-3x-5x2x-12=0
We move all terms containing x to the left, all other terms to the right
-3x-5x2x=12
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