(8/x-4)-5/(x-1)=3

Solution for (8/x-4)-5/(x-1)=3 equation:

(8/x-4)-5/(x-1)=3

We move all terms to the left:

(8/x-4)-5/(x-1)-(3)=0


Domain of the equation: x-4)!=0

x∈R



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R


We get rid of parentheses

8/x-5/(x-1)-4-3=0

We calculate fractions


(8x-8)/(x^2-1x)+(-5x)/(x^2-1x)-4-3=0

We add all the numbers together, and all the variables

(8x-8)/(x^2-1x)+(-5x)/(x^2-1x)-7=0

We multiply all the terms by the denominator


(8x-8)+(-5x)-7*(x^2-1x)=0

We multiply parentheses

-7x^2+(8x-8)+(-5x)+7x=0

We get rid of parentheses

-7x^2+8x-5x+7x-8=0

We add all the numbers together, and all the variables

-7x^2+10x-8=0

a = -7; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·(-7)·(-8)
Δ = -124
Delta is less than zero, so there is no solution for the equation