3(b-2)=2b(b+1)

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Solution for 3(b-2)=2b(b+1) equation: 



3(b-2)=2b(b+1)

We move all terms to the left:

3(b-2)-(2b(b+1))=0

We multiply parentheses

3b-(2b(b+1))-6=0



We calculate terms in parentheses: -(2b(b+1)), so:

2b(b+1)

We multiply parentheses

2b^2+2b

Back to the equation:

-(2b^2+2b)



We get rid of parentheses

-2b^2+3b-2b-6=0

We add all the numbers together, and all the variables

-2b^2+b-6=0

a = -2; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-2)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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