(b-8)/8=(b-9)/2

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Solution for (b-8)/8=(b-9)/2 equation: 



(b-8)/8=(b-9)/2

We move all terms to the left:

(b-8)/8-((b-9)/2)=0

We calculate fractions


b/()+(-((b-9)*8)/()=0



We calculate terms in parentheses: +(-((b-9)*8)/(), so:

-((b-9)*8)/(

We multiply all the terms by the denominator


-((b-9)*8)



We calculate terms in parentheses: -((b-9)*8), so:

(b-9)*8

We multiply parentheses

8b-72

Back to the equation:

-(8b-72)



We get rid of parentheses

-8b+72

Back to the equation:

+(-8b+72)



We get rid of parentheses

b/()-8b+72=0

We multiply all the terms by the denominator


b-8b*()+72*()=0

We add all the numbers together, and all the variables

b-8b*()=0

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