(8/5)z-(2/3)=-(1/2)

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Solution for (8/5)z-(2/3)=-(1/2) equation: 



(8/5)z-(2/3)=-(1/2)

We move all terms to the left:

(8/5)z-(2/3)-(-(1/2))=0



Domain of the equation: 5)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+8/5)z-(+2/3)-(-(+1/2))=0

We multiply parentheses

8z^2-(+2/3)-(-(+1/2))=0

We get rid of parentheses

8z^2-2/3-(-(+1/2))=0

We calculate fractions


8z^2+()/()+()/()=0

We add all the numbers together, and all the variables

8z^2+2=0

a = 8; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·8·2
Δ = -64
Delta is less than zero, so there is no solution for the equation

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