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2x-12+3x+7=2(x+5)-4
We move all terms to the left:
2x-12+3x+7-(2(x+5)-4)=0
We add all the numbers together, and all the variables
5x-(2(x+5)-4)-5=0
We calculate terms in parentheses: -(2(x+5)-4), so:We get rid of parentheses
2(x+5)-4
We multiply parentheses
2x+10-4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
5x-2x-6-5=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3
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