(8/5)z-(3/2)=-(1/2)

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Solution for (8/5)z-(3/2)=-(1/2) equation: 



(8/5)z-(3/2)=-(1/2)

We move all terms to the left:

(8/5)z-(3/2)-(-(1/2))=0



Domain of the equation: 5)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+8/5)z-(+3/2)-(-(+1/2))=0

We multiply parentheses

8z^2-(+3/2)-(-(+1/2))=0

We get rid of parentheses

8z^2-3/2-(-(+1/2))=0

We calculate fractions


8z^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{16}=0$

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