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(8+x)(5x-3)=0
We add all the numbers together, and all the variables
(x+8)(5x-3)=0
We multiply parentheses ..
(+5x^2-3x+40x-24)=0
We get rid of parentheses
5x^2-3x+40x-24=0
We add all the numbers together, and all the variables
5x^2+37x-24=0
a = 5; b = 37; c = -24;
Δ = b2-4ac
Δ = 372-4·5·(-24)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-43}{2*5}=\frac{-80}{10} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+43}{2*5}=\frac{6}{10} =3/5 $
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