4(3+y)=4(2y-1)-12

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Solution for 4(3+y)=4(2y-1)-12 equation: 



4(3+y)=4(2y-1)-12

We move all terms to the left:

4(3+y)-(4(2y-1)-12)=0

We add all the numbers together, and all the variables

4(y+3)-(4(2y-1)-12)=0

We multiply parentheses

4y-(4(2y-1)-12)+12=0



We calculate terms in parentheses: -(4(2y-1)-12), so:

4(2y-1)-12

We multiply parentheses

8y-4-12

We add all the numbers together, and all the variables

8y-16

Back to the equation:

-(8y-16)



We get rid of parentheses

4y-8y+16+12=0

We add all the numbers together, and all the variables

-4y+28=0

We move all terms containing y to the left, all other terms to the right

-4y=-28

y=-28/-4

y=+7

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