2x+3x+3+4x2+10+x=

Solution for 2x+3x+3+4x2+10+x= equation:

2x+3x+3+4x^2+10+x=

We move all terms to the left:

2x+3x+3+4x^2+10+x-()=0

We add all the numbers together, and all the variables

4x^2+6x=0

a = 4; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*4}=\frac{0}{8}
=0
$