7(3b-4)+1=-132

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Solution for 7(3b-4)+1=-132 equation: 



7(3b-4)+1=-132

We move all terms to the left:

7(3b-4)+1-(-132)=0

We add all the numbers together, and all the variables

7(3b-4)+133=0

We multiply parentheses

21b-28+133=0

We add all the numbers together, and all the variables

21b+105=0

We move all terms containing b to the left, all other terms to the right

21b=-105

b=-105/21

b=-5

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