(7x/5)-(3x/2)=(9/10)

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Solution for (7x/5)-(3x/2)=(9/10) equation: 



(7x/5)-(3x/2)=(9/10)

We move all terms to the left:

(7x/5)-(3x/2)-((9/10))=0

We add all the numbers together, and all the variables

(+7x/5)-(+3x/2)-((+9/10))=0

We get rid of parentheses

7x/5-3x/2-((+9/10))=0

We calculate fractions


(-150x^2)/()+140x^2/()+()/()=0

We add all the numbers together, and all the variables

(-150x^2)/()+140x^2/()+1=0

We multiply all the terms by the denominator


(-150x^2)+140x^2+1*()=0

We add all the numbers together, and all the variables

140x^2+(-150x^2)=0

We get rid of parentheses

140x^2-150x^2=0

We add all the numbers together, and all the variables

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$

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