3(7-3z)=2(10-5z)

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Solution for 3(7-3z)=2(10-5z) equation: 



3(7-3z)=2(10-5z)

We move all terms to the left:

3(7-3z)-(2(10-5z))=0

We add all the numbers together, and all the variables

3(-3z+7)-(2(-5z+10))=0

We multiply parentheses

-9z-(2(-5z+10))+21=0



We calculate terms in parentheses: -(2(-5z+10)), so:

2(-5z+10)

We multiply parentheses

-10z+20

Back to the equation:

-(-10z+20)



We get rid of parentheses

-9z+10z-20+21=0

We add all the numbers together, and all the variables

z+1=0

We move all terms containing z to the left, all other terms to the right

z=-1

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