(3/x)=9/(x+4)

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Solution for (3/x)=9/(x+4) equation:



(3/x)=9/(x+4)
We move all terms to the left:
(3/x)-(9/(x+4))=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: (x+4))!=0
x∈R
We add all the numbers together, and all the variables
(+3/x)-(9/(x+4))=0
We get rid of parentheses
3/x-(9/(x+4))=0
We calculate fractions
3x/5x^2+(-(9*x)/5x^2=0
We add all the numbers together, and all the variables
3x/5x^2+(-(+9x)/5x^2=0
We multiply all the terms by the denominator
3x+(-(+9x)=0
We calculate terms in parentheses: +(-(+9x), so:
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We calculate terms in parentheses: +(-(+9x), so:
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