(7x-6)(x+8)=0

Solution for (7x-6)(x+8)=0 equation:

(7x-6)(x+8)=0

We multiply parentheses ..

(+7x^2+56x-6x-48)=0

We get rid of parentheses

7x^2+56x-6x-48=0

We add all the numbers together, and all the variables

7x^2+50x-48=0

a = 7; b = 50; c = -48;
Δ = b2-4ac
Δ = 502-4·7·(-48)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*7}=\frac{-112}{14}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*7}=\frac{12}{14}
=6/7
$