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(7x-6)(9x+2)=0
We multiply parentheses ..
(+63x^2+14x-54x-12)=0
We get rid of parentheses
63x^2+14x-54x-12=0
We add all the numbers together, and all the variables
63x^2-40x-12=0
a = 63; b = -40; c = -12;
Δ = b2-4ac
Δ = -402-4·63·(-12)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-68}{2*63}=\frac{-28}{126} =-2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+68}{2*63}=\frac{108}{126} =6/7 $
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