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7/x+1+3/x-1=6/(x+1)(x-1)
We move all terms to the left:
7/x+1+3/x-1-(6/(x+1)(x-1))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+1)(x-1))!=0We add all the numbers together, and all the variables
x∈R
7/x+3/x-(6/(x+1)(x-1))=0
We use the square of the difference formula
x^2+7/x+3/x+1=0
We multiply all the terms by the denominator
x^2*x+1*x+7+3=0
We add all the numbers together, and all the variables
x^2*x+x+10=0
Wy multiply elements
x^3+x+10=0
We do not support expression: x^3
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