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5(1+2m)=1/5(8+20m)
We move all terms to the left:
5(1+2m)-(1/5(8+20m))=0
Domain of the equation: 5(8+20m))!=0We add all the numbers together, and all the variables
m∈R
5(2m+1)-(1/5(20m+8))=0
We multiply parentheses
10m-(1/5(20m+8))+5=0
We multiply all the terms by the denominator
10m*5(20m+8))-(1+5*5(20m+8))=0
Wy multiply elements
50m^2(2+25m(2=0
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